Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 22

Answer

+30 m/s

Work Step by Step

$a_{1}$ = 1.50$a_{2}$ v = u + at $v_{1}$ = (36.0) + ($a_{1}$)(12) $v_{1}$ = (36.0) + (1.50$a_{2}$)(12) = 36.0 + 18$a_{2}$ v = u + at $v_{2}$ = (36.0 + 18$a_{2}$) + ($a_{2}$)(6) = 36.0 + 24$a_{2}$ 36.0 + 24$a_{2}$ = 28.0 $a_{2}$ = (28.0 - 36.0)/24 = -1/3 $v_{1}$ = 36.0 + 18$a_{2}$ = 36.0 + 18(-1/3) = +30 m/s
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