## Fundamentals of Physics Extended (10th Edition)

$Work$ $Done = 20$ $J$
Work Done is equal to change in kinetic energy. Therefore; $Work$ $Done=\Delta KE$ $Work$ $Done = \frac{1}{2}m(v^{2}-v_{o}^{2})$ $Work$ $Done = \frac{1}{2}\times 2(6^{2}-4^{2})= 36-16 = 20$ $J$