Answer
$Work$ $Done = 20$ $J$
Work Step by Step
Work Done is equal to change in kinetic energy. Therefore;
$Work$ $Done=\Delta KE$
$Work$ $Done = \frac{1}{2}m(v^{2}-v_{o}^{2})$
$Work$ $Done = \frac{1}{2}\times 2(6^{2}-4^{2})= 36-16 = 20$ $J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 171: 9
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