Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems: 9

Answer

$Work$ $Done = 20$ $J$

Work Step by Step

Work Done is equal to change in kinetic energy. Therefore; $Work$ $Done=\Delta KE$ $Work$ $Done = \frac{1}{2}m(v^{2}-v_{o}^{2})$ $Work$ $Done = \frac{1}{2}\times 2(6^{2}-4^{2})= 36-16 = 20$ $J$
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