Answer
Angle between force and displacement $= 118^{\circ}$
Work Step by Step
$Work$ $Done= F.d=F\times d cos\theta$
Work Done is equal to Change in Kinetic Energy which in this case is equal to $=-30J$.
And magnitude of displacement is:
$d= \sqrt {2^{2}+4^{2}+3^{2}}=\sqrt {29}m$
Putting the values and solving we get:
$-30 = 12\times \sqrt {29} cos\theta$
$cos\theta = \frac{-30}{64.6}= -0.464$
$\theta = cos^{-1}(-0.464)$
$\theta=117.64^{\circ} \approx 118^{\circ}$
