Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems: 13e

Answer

$distance = 1.7\times 10^{2}$ $m$

Work Step by Step

They are travelling with an initial velocity of $37 m/s$ and this time, slowing at a rate of $4 m/s^{2}$. Let $d$ be the distance covered while slowing. We know the equation of kinematics, $v^{2}=v_{o}^{2}+2ad$ Putting the known values and solving, we get: $0^{2}=37^{2}+2(-4)d$ $\frac{-37^{2}}{-8}= d $ $d= 171.1$ $m$ $d \approx 1.7\times10^{2}$ $m$
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