Answer
$distance = 1.7\times 10^{2}$ $m$
Work Step by Step
They are travelling with an initial velocity of $37 m/s$ and this time, slowing at a rate of $4 m/s^{2}$. Let $d$ be the distance covered while slowing.
We know the equation of kinematics,
$v^{2}=v_{o}^{2}+2ad$
Putting the known values and solving, we get:
$0^{2}=37^{2}+2(-4)d$
$\frac{-37^{2}}{-8}= d $
$d= 171.1$ $m$
$d \approx 1.7\times10^{2}$ $m$
