# Chapter 7 - Kinetic Energy and Work - Problems: 10

Please see the work below.

#### Work Step by Step

We know that: $W=F_x\Delta x+F_y\Delta_y$ We plug in the know values to obtain: $W=(2.0N)cos(100^{\circ})(3.0m)+(2.0N)sin(100^{\circ})(4.0m)=6.8J$

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