Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 171: 15b


Kinetic energy increases

Work Step by Step

Since net force $=5+(-9cos60^{\circ})=0.5N$, there is some net positive acceleration and that means velocity is increasing at a constant rate. Furthermore, since the expression of Kinetic Energy is $\frac{1}{2}mv^{2}$, an increase in velocity results in an increase in kinetic energy.
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