Answer
$E = 1.25\times 10^5$ megatons of TNT
Work Step by Step
$d = E^{1/3},$ where $d$ is in $km$ and $E$ is in megatons of TNT
If $d = 50~km$, then we can find $E$:
$E^{1/3} = d$
$E = d^3$
$E = (50)^3$
$E = 1.25\times 10^5$ megatons of TNT
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 171: 4a
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