## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 7 - Kinetic Energy and Work - Problems - Page 171: 3b

#### Answer

$0.12$ megatonne of TNT

#### Work Step by Step

To find the number of megatons of TNT equivalent to the impact, divide the energy from the TNT from the energy of impact to get $$=\frac{5\times 10^{14}J}{4.2\times 10^{15}J/MTofTNT}=0.12$$

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