Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 171: 6


$705.6$ J

Work Step by Step

By comparing distances traveled over each second interval, it can be seen that the force decreases the velocity by $4 \frac{m}{s^2}$. This means at time $t=10$, the velocity will be $12-10*4=-28 \frac{m}{s}$, so the kinetic energy will be $\frac{1}{2} *1.8*10^-2 * 784$=$705.6$ J
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