## Fundamentals of Physics Extended (10th Edition)

$705.6$ J
By comparing distances traveled over each second interval, it can be seen that the force decreases the velocity by $4 \frac{m}{s^2}$. This means at time $t=10$, the velocity will be $12-10*4=-28 \frac{m}{s}$, so the kinetic energy will be $\frac{1}{2} *1.8*10^-2 * 784$=$705.6$ J