Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 171: 4b

Answer

$E = 9.62\times 10^6$ Hiroshima bomb equivalents

Work Step by Step

$d = E^{1/3},$ where $d$ is in $km$ and $E$ is in megatons of TNT If $d = 50~km$, then we can find $E$: $E^{1/3} = d$ $E = d^3$ $E = (50)^3$ $E = 1.25\times 10^5$ megatons of TNT We can convert this energy to units of Hiroshima bomb equivalents: $E = (1.25\times 10^8~kilotons~of~TNT)\times (\frac{1~bomb}{13~kilotons ~of~TNT})$ $E = 9.62\times 10^6$ Hiroshima bomb equivalents
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