Answer
The work done on the body by the applied force from $t = 0$ to $t = 2.0~s$ is $~~0.96~J$
Work Step by Step
From the stroboscopic graph, we can see that the body moved $0.2~m$ in a time of $1.0~s$
We can find the acceleration:
$x = \frac{1}{2}at^2$
$a = \frac{2x}{t^2}$
$a = \frac{(2)(0.2~m)}{(1.0~s)^2}$
$a = 0.4~m/s^2$
We can find the magnitude of the force:
$F = ma$
$F = (3.0~kg)(0.4~m/s^2)$
$F = 1.2~N$
We can find the work done on the body by the applied force from $t = 0$ to $t = 2.0~s$:
$W = F~d$
$W = (1.2~N)(0.8~m)$
$W = 0.96~J$
The work done on the body by the applied force from $t = 0$ to $t = 2.0~s$ is $~~0.96~J$
