Answer
$ \sqrt(5) = 2.2$ Newtons
Work Step by Step
Since the vector notation of FNet is Fnet = (1N) i + (-2N) j to find the magnitude we need to use the formula magnitude = $\sqrt(x^2+y^2) $ where x and y are the x and y components (or the i and j components) of the vector, respectively. Therefore we have $\sqrt(1^2 + (-2)^2) = \sqrt (1+4) = \sqrt(5)$
