Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 123: 93a

Answer

$44.1\ N$

Work Step by Step

For mass $m_{2}$, apply Newtons second law of motion so that: $m_{2}(g) - T_1 = m_2(a)$ Since $a=0$; $m_2 g= T_1$ $T_1 = (4.5\ kg)(9.8\ m/s^2)$ $T_1 = 44.1\ N$
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