Answer
$a = 11.8~g$
Work Step by Step
In part (a), we found that the required acceleration is $~~a = 115.7~m/s^2$
We can express the acceleration in units of $g$:
$a = \frac{115.7~m/s^2}{9.8~m/s^2} = 11.8~g$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 5 - Force and Motion-I - Problems - Page 123: 90b
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