Answer
$F= 5786N$
Work Step by Step
$F_{net} = 3F - mg $
$ma = 3F - mg $
$3F= mg + ma $
$F = \frac{mg+ma}{3}$
$F = \frac{(1400kg\times9.8m/s^2)+(1400kg \times 2.6m/s^2}{3}$
$F = 5786$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 5 - Force and Motion-I - Problems - Page 123: 89b
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