Answer
$54\ N$
Work Step by Step
Let tension in the lowest cord be $T_1$.
For mass $m_5$, apply Newtons second law of motion :
$m_5 g - T_1 = m_5 a$
Since it is at rest at $a=0$, then:
$T_1 = m_5 g$
$T_1 = (5.5\ kg)(9.8\ m/s^2)$
$T_1= 54\ N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 5 - Force and Motion-I - Problems - Page 123: 93c
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