Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 123: 89a

Answer

$F = 4573N$

Work Step by Step

At this point the acceleration of the plane is zero which means the net force is also zero: $F_{net} = 3F - mg$ $0= 3F - mg$ $3F = mg$ $F = \frac{mg}{3}$ $F = \frac{1400kg\times9.8m/s^2}{3}$ $F = 4573N$
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