Answer
The tension n the cord is $~~13~N$
Work Step by Step
In part (b), we found that $~~a = 6.5~m/s^2$
We can consider the sliding block to find $F_T$, the tension n the cord:
$F_T = (2.0~kg)(6.5~m/s^2) = 13~N$
The tension n the cord is $~~13~N$
