Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 123: 93b

Answer

$ 78\ N$

Work Step by Step

Let tension at the top of cord be $T_2$. For $m_1$ and $m_2 $, apply newton second law of motion so that; $(m_1+m_2)g - T_2 = (m_1+m_2) a$ Since $a=0$; $T_2 = (m_1+m_2)g$ $T_2 = (3.5\ kg +4.5\ kg) (9.8\ m/s^2)$ $T_2 = 78.4\ N$
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