Answer
$152\ N$
Work Step by Step
Let the tension in the top cord be $T_3 = 199\ N$.
Let Tension in the middle cord and lower cord be $T_2 $ and $T_1$.
Apply Newton's second law of motion for $m_3$ and $m_5$;
$(m_3+m_5)g - (T_1+T_2+T_3) = (m_3+m_5)a $
Since masses are at rest $a = 0$:
$T_1+T_2+T_3 =(m_3+m_5)g $
$T_2 =(m_3+m_5)g - (T_1+T_3) $
$T_2 = (4.8+5.5)9.8-(199+54)$
$T_2=100.9-253$
$T_2=-152\ N$
The negative sign tells that the direction is upwards.
