Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 123: 88b

Answer

$m = 2717kg$

Work Step by Step

The landing craft has an acceleration of $0.39 m/s^2$ at an upward force of $2200N$ Thus the downward force (weight) is calculated by: $F_{d} = F_{net} + F_{u}$ Using this formula to find the mass: $ F_{net} =F_{d} - F_{u}$ $ ma =F_{d} - F_{u}$ $ m =\frac{F_{d} - F_{u}}{a}$ $ m =\frac{3260 - 2200}{0.39}$ $ m = 2717kg$
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