Answer
The new reactance of the inductor is $~~2.60~k\Omega$
Work Step by Step
We can find an expression for the reactance of an inductor:
$X_L = \omega_d~L$
$X_L = 2\pi~f~L$
We can see that if the frequency is doubled, the reactance of the inductor also doubles.
Since the original reactance was $1.30~k\Omega$, the new reactance of the inductor is $2.60~k\Omega$
