Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 939: 59g

Answer

The average rate that energy is dissipated by $R$ is $~~100~W$

Work Step by Step

In part (a), we found that $I_{rms} = 2.586~A$ We can find $P_{ave}$: $P_{ave} = I_{rms}^2~R$ $P_{ave} = (2.586~A)^2~(15.0~\Omega)$ $P_{ave} = 100~W$ The average rate that energy is dissipated by $R$ is $~~100~W$
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