Answer
$V_s=2.4V$
Work Step by Step
We know that
$\frac{V_s}{V_p}=\frac{N_s}{N_p}$
This can be rearranged as:
$V_s=V_p(\frac{N_s}{N_p})$
We plug in the known values to obtain:
$V_s=120(\frac{10}{500})=2.4V$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 939: 63a
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