Answer
$f = 4.60\times 10^3~Hz$
Work Step by Step
We can find the frequency:
$X_L = \omega_d~L$
$X_L = 2\pi~f~L$
$f = \frac{X_L}{2\pi~L}$
$f = \frac{1300~\Omega}{(2\pi)~(45.0\times 10^{-3}~H)}$
$f = 4.60\times 10^3~Hz$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 939: 70a
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
