Answer
There does not necessarily need to be an inductor.
Work Step by Step
We can write an expression for the current:
$i = I~sin~(\omega_d t-\phi)$
In this case, we can see that $\phi = -42.0^{\circ}$
When $\phi \lt 0$, then the circuit is largely capacitive.
Although there must be a capacitor in the box, there does not necessarily need to be an inductor.
The given equation could also be the equation for a RC circuit.
