Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 939: 61g

Answer

There must be a resistor in the box.

Work Step by Step

We can write an expression for the current: $i = I~sin~(\omega_d t-\phi)$ In this case, we can see that $\phi = -42.0^{\circ}$ When $\phi \lt 0$, then the circuit is largely capacitive. Therefore, there must be a capacitor in the box. However, if there is no resistor, then $\phi = -90^{\circ}$ Since $\phi \neq -90^{\circ}$, there must be a resistor in the box.
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