Answer
The circuit is not in resonance.
Work Step by Step
We can write an expression for the current:
$i = I~sin~(\omega_d t-\phi)$
In this case, we can see that $\phi = -42.0^{\circ}$
When a circuit is in resonance, then $\phi = 0$
Since $\phi \neq 0$, the circuit is not in resonance.
