Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 939: 62

Answer

$V_s=1000V$

Work Step by Step

We know that $\frac{V_s}{V_p}=\frac{N_s}{N_p}$ This can be written as: $V_s=\frac{N_s}{N_p}V_p$ We plug in the known values to obtain: $V_s=\frac{500}{50}\times 100=1000V$
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