Answer
$\phi = 1.22~rad$
Work Step by Step
We can find the phase constant:
$tan~\phi = \frac{X_L-X_C}{R}$
$tan~\phi = \frac{\omega_d~L-1/\omega_d~C}{R}$
$tan~\phi = \frac{2\pi~f~L-1/2\pi~f~C}{R}$
$tan~\phi = \frac{(2\pi)~(2000~Hz)~(60.0\times 10^{-3}~H)-1/(2\pi)~(2000~Hz)~(0.400\times 10^{-6}~F)}{200~\Omega}$
$tan~\phi = 2.775193$
$\phi = tan^{-1}~(2.775193)$
$\phi = 1.22~rad$