Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 939: 59e

Answer

$V_{rms} = 64.2~V$

Work Step by Step

In part (c), we found that the $rms$ voltage across $C$ is $159.5~V$ In part (d), we found that the $rms$ voltage across $L$ is $223.7~V$ Note that the potential difference (high potential and low potential) across each of these devices is aligned in opposite directions as we move through the circuit. We can find the $rms$ voltage across $C$ and $L$ together: $V_{rms} = 223.7~V-159.5~V = 64.2~V$
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