Answer
$C = 117~\mu F$
Work Step by Step
The average rate at which energy is dissipated in the resistor is a maximum when the current amplitude is a maximum. This situation occurs at resonance.
We can find the required value of the capacitance:
$\omega_d = \frac{1}{\sqrt{L~C}}$
$2\pi~f_d = \frac{1}{\sqrt{L~C}}$
$4\pi^2~f_d^2 = \frac{1}{L~C}$
$C = \frac{1}{4\pi^2~f_d^2~L}$
$C = \frac{1}{(4\pi^2)~(60.0~Hz)^2~(60.0\times 10^{-3}~H)}$
$C = 117~\mu F$
