Answer
$I = 0.165~A$
Work Step by Step
In part (a), we found that $Z = 218~\Omega$
We can find $I$:
$I = \frac{\mathscr{E}_m}{Z}$
$I = \frac{36.0~V}{218~\Omega}$
$I = 0.165~A$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 938: 43c
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