Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 938: 47b

Answer

$I = 6.00~A$

Work Step by Step

We can find the current amplitude at resonance: $I = \frac{\mathscr{E}_m}{R}$ $I = \frac{30.0~V}{5.00~\Omega}$ $I = 6.00~A$
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