Answer
$X_C = 16.6~\Omega$
Work Step by Step
We can find $X_C$:
$X_C = \frac{1}{\omega_d~C}$
$X_C = \frac{1}{2\pi~f_d~C}$
$X_C = \frac{1}{(2\pi)~(400~Hz)~(24.0\times 10^{-6}~F)}$
$X_C = 16.6~\Omega$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 938: 44a
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