Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 938: 50b

Answer

$f_d = 318~Hz$

Work Step by Step

We can write an expression for $V_R$: $V_R= I_R~R$ We can write an expression for $V_L$: $V_L= I_L~X_L$ We can equate the two expressions to find $f_d$: $V_R = V_L$ $I_R~R = I_L~X_L$ $R = X_L$ $R = \omega_d~L$ $R = 2\pi~f_d~L$ $f_d = \frac{R}{2\pi~L}$ $f_d = \frac{80.0~\Omega}{(2\pi)~(40.0\times 10^{-3}~H)}$ $f_d = 318~Hz$
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