Answer
The average rate at which energy is supplied to the appliance is $~~1190~W$
Work Step by Step
In part (a), we found that the impedance is $Z = 12.07~\Omega$
We can find $I_{rms}$:
$I_{rms} = \frac{\mathscr{E}_{rms}}{Z}$
$I_{rms} = \frac{120~V}{12.07~\Omega}$
$I_{rms} = 9.942~A$
We can find the average power:
$P_{ave} = I_{rms}^2~R$
$P_{ave} = (9.942~A)^2~(12.0~\Omega)$
$P_{ave} = 1190~W$
The average rate at which energy is supplied to the appliance is $~~1190~W$
