Answer
$L = 60~mH$
Work Step by Step
On the graph, we can see that $X_L = 120~\Omega$ when $\omega_d = 2000~rad/s$
We can find $L$:
$X_L = \omega_d~L$
$L = \frac{X_L}{\omega_d}$
$L = \frac{120~\Omega}{2000~rad/s}$
$L = 60~mH$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 938: 42b
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