Answer
Yes, it is possible for the amplitude of the voltage across the inductor to be greater than the amplitude of the generator emf.
Work Step by Step
At resonance, $\omega_d = \frac{1}{\sqrt{L~C}}$ and $I = \frac{\mathscr{E}_m}{R}$
We can find an expression for the amplitude of the voltage across the inductor:
$V_L = I_L~X_L$
$V_L = \frac{\mathscr{E}_m~\omega_d~L}{R}$
$V_L = \frac{\mathscr{E}_m}{R}~\sqrt{\frac{L}{C}}$
If $~~\frac{1}{R}~\sqrt{\frac{L}{C}} \gt 1$, then the amplitude of the voltage across the inductor is greater than the amplitude of the generator emf.
Yes, it is possible for the amplitude of the voltage across the inductor to be greater than the amplitude of the generator emf.
