Answer
The value of $I$ increases.
Work Step by Step
In part (e), we found that the new impedance is $Z = 408~\Omega$
The original value of $I$ was $0.521~A$
We can find the new value of $I$:
$I = \frac{\mathscr{E}_m}{Z}$
$I = \frac{220~V}{408~\Omega}$
$I = 0.539~A$
The value of $I$ increases.
