Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 936: 9

Answer

$7.0\times10^{-4}\,s$

Work Step by Step

$\omega=\frac{2\pi}{T}=\frac{1}{\sqrt {LC}}$ $\implies T=2\pi\sqrt {LC}$ $\frac{T}{4}$ time is taken to attain full charge. $\implies t=\frac{T}{4}=\frac{2\pi\sqrt {LC}}{4}=\frac{\pi\sqrt {50\times10^{-3}H\times4.0\times10^{-6}F}}{2}=7.0\times10^{-4}\,s$
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