Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 936: 10

Answer

$L=3.8\times 10^{-5}H$

Work Step by Step

We know that; $\omega=2\pi f$ $\omega=2(3.1416)(10000)=62832\frac{rad}{s}$ Also, $\omega=\sqrt\frac{1}{LC}$ This can be rearranged as: $L=\frac{1}{C\omega^2}$ We plug in the known values to obtain: $L=\frac{1}{6.7\times 10^{-6}(62832)^2}=3.8\times 10^{-5}H$
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