Answer
$\omega=89\frac{rad}{s}$
Work Step by Step
We know that;
$K=\frac{F}{x}$
We substitute the values of $F$ and $x$ to find $K$;
$K=\frac{8}{0.002}=4000\frac{N}{m}$
The angular frequency can be determined as
$\omega=\sqrt\frac{K}{m}$
We plug in the known values to obtain:
$\omega=\sqrt\frac{4000}{0.50}=89.44=89\frac{rad}{s}$
