Answer
The total energy is $~~3.20\times 10^{-3}~J$
Work Step by Step
We can state the expression for the current:
$i = (1.60)~sin~(2500 t+0.680)$
Note that the maximum current is $I = 1.60~A$
In part (b), we found that $L = 2.50~mH$
We can find the energy stored in the magnetic field when it stores all the energy in the system:
$U_B = \frac{L~I^2}{2}$
$U_B = \frac{(2.50\times 10^{-3}~H)~(1.60~A)^2}{2}$
$U_B = 3.20\times 10^{-3}~J$
The total energy is $~~3.20\times 10^{-3}~J$
