Answer
$C=25\mu$F
Work Step by Step
We know that;
$\omega=\sqrt\frac{1}{LC}$
This can be rearranged as:
$C=\frac{1}{L\omega^2}$
We plug in the known values to obtain:
$C=\frac{1}{5.0(89.44)^2}=25\times 10^{-6}=25\mu F$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 936: 6c
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