Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 936: 12b

Answer

$0.866~~$ of the maximum current is in the inductor.

Work Step by Step

We can write an expression for the energy stored in the magnetic field when the maximum current $I$ is in the inductor: $U_B = \frac{L~I^2}{2}$ We can find the current $i$ when $75.0\%$ of the energy is stored in the magnetic field: $\frac{L~i^2}{2}= 0.75~\frac{L~I^2}{2}$ $i^2= 0.75~I^2$ $i= 0.866~I$ $0.866~~$ of the maximum current is in the inductor.
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