Answer
$t=4.77\mu s$
Work Step by Step
f = 1/T
From previous value we can write
f = 1.33×10^3
Thus, time period T = 7.54×10^-4
This gives time required to charge capacitor maximum is
t= T/4.
t= 1.88 ×10^-4 sec
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 936: 20c
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