Answer
$F = 0.18~N$
Work Step by Step
We can find the required external force:
$F = \frac{B^2~L^2~v}{R}$
$F = \frac{(1.2~T)^2~(0.10~m)^2~(5.0~m/s)}{0.40~\Omega}$
$F = 0.18~N$
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