Answer
$i = 6.00\times 10^{-4}~A$
Work Step by Step
In part (a), we found that the induced emf is $~~\mathscr{E} = 2.40\times 10^{-4}~V$
We can find the induced current:
$i = \frac{\mathscr{E}}{R}$
$i = \frac{2.40\times 10^{-4}~V}{0.400~\Omega}$
$i = 6.00\times 10^{-4}~A$
