Answer
$F = 2.88\times 10^{-8}~N$
Work Step by Step
In part (c), we found that the power in the loop is $1.44\times 10^{-7}~W$
We can find the required force:
$F~v = P$
$F = \frac{P}{v}$
$F = \frac{1.44\times 10^{-7}~W}{5.00~m/s}$
$F = 2.88\times 10^{-8}~N$
